fix: resolve flow type error

Author: xyy94813

src/libs/getComponentNameFromType.js

@@ -4,7 +4,7 @@
  * @flow
  */
 
-import type { LazyComponent, ReactContext, ReactProviderType } from 'react';
+import type { Context, StatelessFunctionalComponent } from 'react';
 import { Fragment } from 'react';
 import {
   ContextConsumer,
@@ -20,6 +20,16 @@ import {
   Lazy,
 } from 'react-is';
 
+/**
+ * didn't export the type in React
+ * same as https://github.com/facebook/react/blob/310187264d01a31bc3079358f13662d31a079d9e/packages/react/index.js
+ */
+type LazyComponent<T, P> = {
+  $$typeof: Symbol | number,
+  _payload: P,
+  _init: (payload: P) => T,
+};
+
 // Keep in sync with react-reconciler/getComponentNameFromFiber
 function getWrappedName(
   outerType: mixed,
@@ -35,7 +45,7 @@ function getWrappedName(
 }
 
 // Keep in sync with react-reconciler/getComponentNameFromFiber
-function getContextName(type: ReactContext<any>) {
+function getContextName(type: Context<any>) {
   return type.displayName || 'Context';
 }
 
@@ -72,23 +82,28 @@ function getComponentNameFromType(type: mixed): string | null {
   if (typeof type === 'object') {
     // eslint-disable-next-line default-case
     switch (type.$$typeof) {
-      case ContextConsumer:
+      case ContextConsumer: {
         /**
          * in DEV, should get context from `_context`.
          * https://github.com/facebook/react/blob/e16d61c3000e2de6217d06b9afad162e883f73c4/packages/react/src/ReactContext.js#L44-L125
          */
-        return `${getContextName(type._context ?? type)}.Consumer`;
-      case ContextProvider:
-        return `${getContextName(type._context)}.Provider`;
+        const context: any = type._context ?? type;
+        return `${getContextName(context)}.Consumer`;
+      }
+      case ContextProvider: {
+        const context: any = type._context;
+        return `${getContextName(context)}.Provider`;
+      }
       case ForwardRef:
         // eslint-disable-next-line no-case-declarations
         return getWrappedName(type, type.render, 'ForwardRef');
-      case Memo:
+      case Memo: {
         const outerName = (type: any).displayName || null;
         if (outerName !== null) {
           return outerName;
         }
         return getComponentNameFromType(type.type) || 'Memo';
+      }
       case Lazy: {
         const lazyComponent: LazyComponent<any, any> = (type: any);
         const payload = lazyComponent._payload;