From 1a292ae9eb3e39f23e05683e484b26abbe8b017c Mon Sep 17 00:00:00 2001
From: filipapietrat <filipapietrat@gmail.com>
Date: Wed, 29 Nov 2023 14:06:54 +0000
Subject: [PATCH] [lab-sql-self-cross-join]Filipa T

---
 [lab-sql-self-cross-join]Filipa T.sql | 51 +++++++++++++++++++++++++++
 1 file changed, 51 insertions(+)
 create mode 100644 [lab-sql-self-cross-join]Filipa T.sql

diff --git a/[lab-sql-self-cross-join]Filipa T.sql b/[lab-sql-self-cross-join]Filipa T.sql
new file mode 100644
index 0000000..9a091f1
--- /dev/null
+++ b/[lab-sql-self-cross-join]Filipa T.sql	
@@ -0,0 +1,51 @@
+-- 1. Get all pairs of actors that worked together.
+
+create temporary table sakila.pairs_actors as
+select fa1.actor_id as actor1_id, fa1.film_id as film1_id,
+       fa2.actor_id as actor2_id, fa2.film_id as film2_id
+from sakila.film_actor fa1
+inner join sakila.film_actor fa2
+on fa1.actor_id <> fa2.actor_id
+and fa1.film_id = fa2.film_id
+order by fa1.film_id, fa1.actor_id
+;
+
+select p.actor1_id, a1.first_name, a1.last_name, p.film1_id, f1.title, p.film2_id, p.actor2_id, a2.first_name, a2.last_name
+from sakila.pairs_actors p
+left join sakila.film f1 on p.film1_id = f1.film_id
+left join sakila.film f2 on p.film2_id = f2.film_id
+left join sakila.actor a1 on p.actor1_id = a1.actor_id
+left join sakila.actor a2 on p.actor2_id = a2.actor_id
+;
+
+-- 2. Get all pairs of customers that have rented the same film more than 3 times.
+
+select c1.customer_id, c2.customer_id, count(distinct r1.inventory_id) as number_of_rentals
+from sakila.customer as c1
+inner join sakila.rental as r1
+on c1.customer_id = r1.customer_id
+inner join sakila.inventory as i1
+on r1.inventory_id = i1.inventory_id
+inner join sakila.film as f
+on i1.film_id = f.film_id
+inner join sakila.inventory as i2
+on f.film_id = i2.film_id
+inner join sakila.rental as r2
+on i2.inventory_id = r2.inventory_id
+inner join sakila.customer as c2
+on r2.customer_id = c2.customer_id
+where c1.customer_id <> c2.customer_id
+group by 1,2
+having number_of_rentals >3
+order by 3 desc
+;
+
+
+
+-- 3. Get all possible pairs of actors and films.
+
+
+select distinct f.title, a.first_name as actor_first_name, a.last_name as actor_last_name
+from sakila.film_actor fa
+cross join sakila.film f
+left join sakila.actor a on fa.actor_id = a.actor_id;
\ No newline at end of file