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Original file line number Diff line number Diff line change
@@ -1,28 +1,55 @@
# [1625.Lexicographically Smallest String After Applying Operations][title]

> [!WARNING|style:flat]
> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)

## Description
You are given a string `s` of **even length** consisting of digits from `0` to `9`, and two integers `a` and `b`.

You can apply either of the following two operations any number of times and in any order on `s`:

- Add `a` to all odd indices of `s` (**0-indexed**). Digits post `9` are cycled back to `0`. For example, if `s = "3456"` and `a = 5`, `s` becomes `"3951"`.
- Rotate `s` to the right by `b` positions. For example, if `s = "3456"` and `b = 1`, s becomes `"6345"`.

Return the **lexicographically smallest** string you can obtain by applying the above operations any number of times on s.

A string `a` is lexicographically smaller than a string `b` (of the same length) if in the first position where `a` and `b` differ, string a has `a` letter that appears earlier in the alphabet than the corresponding letter in `b`. For example, `"0158"` is lexicographically smaller than `"0190"` because the first position they differ is at the third letter, and `'5'` comes before `'9'`.

**Example 1:**

```
Input: a = "11", b = "1"
Output: "100"
Input: s = "5525", a = 9, b = 2
Output: "2050"
Explanation: We can apply the following operations:
Start: "5525"
Rotate: "2555"
Add: "2454"
Add: "2353"
Rotate: "5323"
Add: "5222"
Add: "5121"
Rotate: "2151"
Add: "2050"
There is no way to obtain a string that is lexicographically smaller than "2050".
```

## 题意
> ...
**Example 2:**

## 题解

### 思路1
> ...
Lexicographically Smallest String After Applying Operations
```go
```
Input: s = "74", a = 5, b = 1
Output: "24"
Explanation: We can apply the following operations:
Start: "74"
Rotate: "47"
Add: "42"
Rotate: "24"
There is no way to obtain a string that is lexicographically smaller than "24".
```

**Example 3:**

```
Input: s = "0011", a = 4, b = 2
Output: "0011"
Explanation: There are no sequence of operations that will give us a lexicographically smaller string than "0011".
```

## 结语

Expand Down
Original file line number Diff line number Diff line change
@@ -1,5 +1,32 @@
package Solution

func Solution(x bool) bool {
return x
func Solution(s string, a int, b int) string {
n := len(s)
vis := make([]bool, n)
res := s
s = s + s
for i := 0; !vis[i]; i = (i + b) % n {
vis[i] = true
for j := 0; j < 10; j++ {
kLimit := 0
if b%2 != 0 {
kLimit = 9
}
for k := 0; k <= kLimit; k++ {
// before each accumulation, re-truncate t
t := []byte(s[i : i+n])
for p := 1; p < n; p += 2 {
t[p] = '0' + byte((int(t[p]-'0')+j*a)%10)
}
for p := 0; p < n; p += 2 {
t[p] = '0' + byte((int(t[p]-'0')+k*a)%10)
}
tStr := string(t)
if tStr < res {
res = tStr
}
}
}
}
return res
}
Original file line number Diff line number Diff line change
Expand Up @@ -10,30 +10,31 @@ func TestSolution(t *testing.T) {
// 测试用例
cases := []struct {
name string
inputs bool
expect bool
s string
a, b int
expect string
}{
{"TestCase", true, true},
{"TestCase", true, true},
{"TestCase", false, false},
{"TestCase1", "5525", 9, 2, "2050"},
{"TestCase2", "74", 5, 1, "24"},
{"TestCase3", "0011", 4, 2, "0011"},
}

// 开始测试
for i, c := range cases {
t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
got := Solution(c.inputs)
got := Solution(c.s, c.a, c.b)
if !reflect.DeepEqual(got, c.expect) {
t.Fatalf("expected: %v, but got: %v, with inputs: %v",
c.expect, got, c.inputs)
t.Fatalf("expected: %v, but got: %v, with inputs: %v %v %v",
c.expect, got, c.s, c.a, c.b)
}
})
}
}

// 压力测试
// 压力测试
func BenchmarkSolution(b *testing.B) {
}

// 使用案列
// 使用案列
func ExampleSolution() {
}
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