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46 changes: 46 additions & 0 deletions C++/Solution#3.cpp
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/*
3. Longest Substring Without Repeating Characters
Medium


Given a string s, find the length of the longest substring without repeating characters.



Example 1:

Input: s = "abcabcbb"
Output: 3
Explanation: The answer is "abc", with the length of 3.
Example 2:

Input: s = "bbbbb"
Output: 1
Explanation: The answer is "b", with the length of 1.

*/

class Solution {
public:
int lengthOfLongestSubstring(string s) {
int beg=0;
int end=0;
unsigned long int len=0;
set<char> st;
while(end<s.length())
{
if(!(st.count(s[end])))
{
st.insert(s[end]);
len=max(st.size(),len);
end++;
}
else
{
st.erase(s[beg]);
beg++;
}
}
return len;
}
};
57 changes: 57 additions & 0 deletions C++/Solution#42.cpp
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/*
42. Trapping Rain Water
Hard

Example 1:


Input: height = [0,1,0,2,1,0,1,3,2,1,2,1]
Output: 6
Explanation: The above elevation map (black section) is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain water (blue section) are being trapped.
Example 2:

Input: height = [4,2,0,3,2,5]
Output: 9

*/

class Solution {
public:
int trap(vector<int>& height) {
if(height.size()==0)
return 0;
int i,pi=0,wt=0,s=(int)(height.size()-1),tp=0;
int p=height[0];
for(i=1;i<=s;i++)
{
if(height[i]>p)
{
pi=i;
p=height[i];
tp=0;
}
else
{
wt+=p-height[i];
tp+=p-height[i];
}
}
if(pi<s)
{
wt-=tp;
p=height[s];
for(i=s-1;i>=pi;i--)
{
if(height[i] >= p)
{
p = height[i];
}
else
{
wt += p - height[i];
}
}
}
return wt;
}
};
2 changes: 2 additions & 0 deletions Contributors.md
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Expand Up @@ -29,3 +29,5 @@

**Caitlin Genna** --> "CS Computer Science Graduate, Fordham University." --> [caitlingenna](https://github.com/caitlingenna)

**Utkarsh Nigam** --> "Learner | C.S undergrad" --> [utkarsh-7](https://github.com/utkarsh-7)